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General
Easy

Question

If the differential equation representing the family of all circles touching x‐axis at the origin is left parenthesis x to the power of 2 end exponent minus y to the power of 2 end exponent right parenthesis fraction numerator d y over denominator d x end fraction equals g left parenthesis x right parenthesis y comma t h e n g left parenthesis x right parenthesis equals

  1. fraction numerator 1 over denominator 2 end fraction x    
  2. 2 x to the power of 2 end exponent    
  3. 2x    
  4. fraction numerator 1 over denominator 2 end fraction x to the power of 2 end exponent    

The correct answer is: 2x


    Equation of family is left parenthesis x minus 0 right parenthesis to the power of 2 end exponent plus left parenthesis y minus 0 right parenthesis to the power of 2 end exponent equals 0 to the power of 2 end exponent

    x to the power of 2 end exponent plus y to the power of 2 end exponent plus 0 to the power of 2 end exponent minus 20 y equals 0 to the power of 2 end exponent
    rightwards double arrow x to the power of 2 end exponent plus y to the power of 2 end exponent minus 20 y equals 0 (1)
    On differentiating Eq (1), we get
    2 x plus 2 y fraction numerator d y over denominator d x end fraction minus 20 fraction numerator d y over denominator d x end fraction equals 0 equals x equals fraction numerator d y over denominator d x end fraction left parenthesis 0 minus y right parenthesis
    a equals fraction numerator x over denominator d y l d x end fraction plus y (2)
    From Eqs (1) and (2), we get
    x to the power of 2 end exponent plus y to the power of 2 end exponent minus 2 left parenthesis fraction numerator x over denominator d y l d x end fraction plus y right parenthesis y equals 0 equals x to the power of 2 end exponent plus y to the power of 2 end exponent minus fraction numerator 2 x y over denominator d y l d x end fraction 2 y to the power of 2 end exponent equals 0
    x to the power of 2 end exponent minus y to the power of 2 end exponent minus fraction numerator 2 x y over denominator d y l d x end fraction equals 0 equals left parenthesis x to the power of 2 end exponent minus y to the power of 2 end exponent right parenthesis fraction numerator d y over denominator d x end fraction equals 2 x y equals g left parenthesis x right parenthesis y equals g left parenthesis x right parenthesis equals 2 x
    Hence, the correct answer is option (C).

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