Maths-
General
Easy

Question

If the four faces of a tetrahedron are represented by the equations r with minus on top times left parenthesis alpha i with minus on top plus beta j with minus on top right parenthesis equals 0 comma r with minus on top times left parenthesis beta j with minus on top plus gamma k with minus on top right parenthesis equals 0 comma r with minus on top times left parenthesis gamma k with minus on top plus alpha i with minus on top right parenthesis equals 0 and r with minus on top times left parenthesis alpha i with minus on top plus beta j with minus on top plus gamma k with minus on top right parenthesis equals P then volume of the tetrahedron (in cubic units) is

  1. open vertical bar fraction numerator P to the power of 3 end exponent over denominator 6 alpha beta gamma end fraction close vertical bar    
  2. open vertical bar fraction numerator 4 P to the power of 3 end exponent over denominator 6 alpha beta gamma end fraction close vertical bar    
  3. open vertical bar fraction numerator 3 P to the power of 3 end exponent over denominator 6 alpha beta gamma end fraction close vertical bar    
  4. none of these    

The correct answer is: open vertical bar fraction numerator 4 P to the power of 3 end exponent over denominator 6 alpha beta gamma end fraction close vertical bar


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