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Maths-

General

Easy

Question

If the rate of change of sine of an angle $theta$ is $k$ , then the rate of change of its tangent is

$k^{2}$
$\frac{1}{k^{2}}$
$k$
$\frac{1}{k}$

The correct answer is: $fraction numerator 1 over denominator k to the power of 2 end exponent end fraction$

$fraction numerator d over denominator d theta end fraction open parentheses sin invisible function application theta close parentheses equals k rightwards double arrow cos invisible function application theta equals k$
$therefore fraction numerator d over denominator d theta end fraction open parentheses tan invisible function application theta close parentheses equals sec to the power of 2 end exponent invisible function application theta equals fraction numerator 1 over denominator k to the power of 2 end exponent end fraction$

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