Maths-
General
Easy

Question

If x subscript 1 end subscript blank a n d blank x subscript 2 end subscript are the roots of the equation e to the power of 2 end exponent blank. x to the power of ln invisible function application x end exponent equals x to the power of 3 end exponent blank w i t h blank x subscript 1 end subscript greater than x subscript 2 end subscript comma then

  1. x subscript 1 end subscript equals 2 x subscript 2 end subscript  
  2. x subscript 1 end subscript equals x subscript 2 end subscript superscript 2 end superscript  
  3. 2 x subscript 1 end subscript equals x subscript 2 end subscript superscript 2 end superscript  
  4. x subscript 1 end subscript superscript 2 end superscript equals x subscript 2 end subscript superscript 3 end superscript  

The correct answer is: x subscript 1 end subscript equals x subscript 2 end subscript superscript 2 end superscript


    e to the power of 2 end exponent bullet x to the power of ln invisible function application x end exponent equals x to the power of 3 end exponent
    Taking log on both sides, we get ln invisible function application open parentheses e to the power of 2 end exponent bullet x to the power of ln invisible function application x end exponent close parentheses equals ln invisible function application open parentheses x to the power of 3 end exponent close parentheses
    rightwards double arrow open parentheses ln invisible function application x close parentheses to the power of 2 end exponent minus 3 ln invisible function application x plus 2 equals 0
    rightwards double arrow open parentheses ln invisible function application x minus 2 close parentheses open parentheses ln invisible function application x minus 1 close parentheses equals 0
    If ln invisible function application x equals 2 rightwards double arrow x equals e to the power of 2 end exponent
    If ln invisible function application x equals 1 rightwards double arrow x equals e
    Since x subscript 1 end subscript greater than x subscript 2 end subscript comma blank w e blank g e t blank x subscript 1 end subscript equals e to the power of 2 end exponent blank a n d blank x subscript 2 end subscript equals e
    rightwards double arrow x subscript 2 end subscript superscript 2 end superscript equals x subscript 1 end subscript

    Related Questions to study

    General
    Maths-

    sec to the power of 2 end exponent invisible function application theta equals fraction numerator 4 x y over denominator open parentheses x plus y close parentheses to the power of 2 end exponent end fraction is true if and only if

    sec to the power of 2 end exponent invisible function application theta equals fraction numerator 4 x y over denominator open parentheses x plus y close parentheses to the power of 2 end exponent end fraction is true if and only if

    Maths-General
    General
    Maths-

    Product of roots of the equation fraction numerator log subscript 8 end subscript invisible function application open parentheses 8 divided by x to the power of 2 end exponent close parentheses over denominator open parentheses log subscript 8 end subscript invisible function application x close parentheses to the power of 2 end exponent end fraction equals 3 is

    Product of roots of the equation fraction numerator log subscript 8 end subscript invisible function application open parentheses 8 divided by x to the power of 2 end exponent close parentheses over denominator open parentheses log subscript 8 end subscript invisible function application x close parentheses to the power of 2 end exponent end fraction equals 3 is

    Maths-General
    General
    Maths-

    The value of the expression fraction numerator 2 open parentheses sin invisible function application 1 degree plus sin invisible function application 2 degree plus sin invisible function application 3 degree plus horizontal ellipsis plus sin invisible function application 89 degree close parentheses over denominator 2 open parentheses cos invisible function application 1 degree plus cos invisible function application 2 degree plus horizontal ellipsis plus cos invisible function application 44 degree close parentheses plus 1 end fraction equals

    The value of the expression fraction numerator 2 open parentheses sin invisible function application 1 degree plus sin invisible function application 2 degree plus sin invisible function application 3 degree plus horizontal ellipsis plus sin invisible function application 89 degree close parentheses over denominator 2 open parentheses cos invisible function application 1 degree plus cos invisible function application 2 degree plus horizontal ellipsis plus cos invisible function application 44 degree close parentheses plus 1 end fraction equals

    Maths-General
    parallel
    General
    Maths-

    Inblank increment A B C comma ifblank A equals 30 degree comma blank b equals 2 comma blank c equals square root of 3 plus 1 comma blankthenfraction numerator C minus B over denominator 2 end fraction blankis equal to

    Inblank increment A B C comma ifblank A equals 30 degree comma blank b equals 2 comma blank c equals square root of 3 plus 1 comma blankthenfraction numerator C minus B over denominator 2 end fraction blankis equal to

    Maths-General
    General
    Maths-

    I f blank x comma blank y comma blank z blank a r e blank i n blank A. P comma blank t h e n fraction numerator sin invisible function application x minus sin invisible function application z over denominator cos invisible function application z minus cos invisible function application x end fraction blank i s blank e q u a l blank t o

    I f blank x comma blank y comma blank z blank a r e blank i n blank A. P comma blank t h e n fraction numerator sin invisible function application x minus sin invisible function application z over denominator cos invisible function application z minus cos invisible function application x end fraction blank i s blank e q u a l blank t o

    Maths-General
    General
    Maths-

    The general value of x satisfying the equation 2 cot to the power of 2 end exponent invisible function application x plus 2 square root of 3 cot invisible function application x plus 4 blank c o s e c blank x plus 8 equals 0 is

    The general value of x satisfying the equation 2 cot to the power of 2 end exponent invisible function application x plus 2 square root of 3 cot invisible function application x plus 4 blank c o s e c blank x plus 8 equals 0 is

    Maths-General
    parallel
    General
    Maths-

    If open parentheses 21.4 close parentheses to the power of a end exponent equals open parentheses 0.00214 close parentheses to the power of b end exponent equals 100 comma then the value of fraction numerator 1 over denominator b end fraction minus fraction numerator 1 over denominator b end fraction is

    If open parentheses 21.4 close parentheses to the power of a end exponent equals open parentheses 0.00214 close parentheses to the power of b end exponent equals 100 comma then the value of fraction numerator 1 over denominator b end fraction minus fraction numerator 1 over denominator b end fraction is

    Maths-General
    General
    Maths-

    In triangle A B C comma fraction numerator a over denominator b end fraction equals fraction numerator 2 over denominator 3 end fraction blankand sec to the power of 2 end exponent invisible function application A equals fraction numerator 8 over denominator 5 end fraction. Then the number of triangles satisfying these conditions is

    In triangle A B C comma fraction numerator a over denominator b end fraction equals fraction numerator 2 over denominator 3 end fraction blankand sec to the power of 2 end exponent invisible function application A equals fraction numerator 8 over denominator 5 end fraction. Then the number of triangles satisfying these conditions is

    Maths-General
    General
    Maths-

    The greatest value of sin to the power of 4 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta is

    The greatest value of sin to the power of 4 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta is

    Maths-General
    parallel
    General
    Maths-

    If in a increment A B C comma cos invisible function application 3 A plus cos invisible function application 3 B plus cos invisible function application 3 C equals 1 comma blankthen one angle must be exactly equal to

    If in a increment A B C comma cos invisible function application 3 A plus cos invisible function application 3 B plus cos invisible function application 3 C equals 1 comma blankthen one angle must be exactly equal to

    Maths-General
    General
    Maths-

    The solution of 4 sin to the power of 2 end exponent invisible function application x plus tan to the power of 2 end exponent invisible function application x plus c o s e c to the power of 2 end exponent x plus cot to the power of 2 end exponent invisible function application x minus 6 equals 0 is

    The solution of 4 sin to the power of 2 end exponent invisible function application x plus tan to the power of 2 end exponent invisible function application x plus c o s e c to the power of 2 end exponent x plus cot to the power of 2 end exponent invisible function application x minus 6 equals 0 is

    Maths-General
    General
    Maths-

    In triangle A B C comma blankifblank A minus B equals 120 degree blankandblank R equals 8 r where R blankandblank r have their usual meaning, then cos invisible function application C equals

    In triangle A B C comma blankifblank A minus B equals 120 degree blankandblank R equals 8 r where R blankandblank r have their usual meaning, then cos invisible function application C equals

    Maths-General
    parallel
    General
    Maths-

    In the given figure, A B is the diameter of the circle, centered at ´ O to the power of ´ end exponent. If angle C O A equals 60 degree comma blank A B equals 2 r comma blank A C equals d blankandblank C D equals l comma then l is equal to

    In the given figure, A B is the diameter of the circle, centered at ´ O to the power of ´ end exponent. If angle C O A equals 60 degree comma blank A B equals 2 r comma blank A C equals d blankandblank C D equals l comma then l is equal to
    Maths-General

    General
    Maths-

    I f tan invisible function application x equals n tan invisible function application y comma blank n element of R to the power of plus end exponent comma then the maximum value of s e c to the power of 2 end exponent open parentheses x minus y close parentheses is equal to

    I f tan invisible function application x equals n tan invisible function application y comma blank n element of R to the power of plus end exponent comma then the maximum value of s e c to the power of 2 end exponent open parentheses x minus y close parentheses is equal to

    Maths-General
    General
    Maths-

    If the equation 2 to the power of x end exponent plus 4 to the power of y end exponent equals 2 to the power of y end exponent plus 4 to the power of x end exponent is solved for y in terms of x comma blankwhere x less than 0 comma then the sum of the solutions is

    If the equation 2 to the power of x end exponent plus 4 to the power of y end exponent equals 2 to the power of y end exponent plus 4 to the power of x end exponent is solved for y in terms of x comma blankwhere x less than 0 comma then the sum of the solutions is

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.