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I f sin to the power of negative 1 end exponent invisible function application a plus sin to the power of negative 1 end exponent invisible function application b plus sin to the power of negative 1 end exponent invisible function application c equals pi, thenblank a square root of 1 minus a to the power of 2 end exponent end root plus b square root of 1 minus b to the power of 2 end exponent end root plus c square root of 1 minus c to the power of 2 end exponent end root is equal to

  1. a plus b plus c  
  2. a to the power of 2 end exponent b to the power of 2 end exponent c to the power of 2 end exponent  
  3. 2 a b c  
  4. 4 a b c  

The correct answer is: 2 a b c


    L e t blank A equals sin to the power of negative 1 end exponent invisible function application a comma blank B equals s i n to the power of negative 1 end exponent b blank a n d blank C equals sin to the power of negative 1 end exponent invisible function application c comma blank w e blank h a v e blank A plus B plus C equals pi.
    a square root of 1 minus a to the power of 2 end exponent end root plus b square root of 1 minus b to the power of 2 end exponent end root plus c square root of 1 minus c to the power of 2 end exponent end root equals fraction numerator 1 over denominator 2 end fraction open parentheses sin invisible function application 2 A plus sin invisible function application 2 B plus sin invisible function application 2 C close parentheses
    equals fraction numerator 1 over denominator 2 end fraction open square brackets 4 sin invisible function application A sin invisible function application B sin invisible function application C close square brackets
    equals 2 blank a b c

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