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In any triangle A B C comma sin to the power of 2 end exponent invisible function application A minus sin to the power of 2 end exponent invisible function application B plus sin to the power of 2 end exponent invisible function application C is always equal to

  1. 2 sin invisible function application A sin invisible function application B cos invisible function application C  
  2. 2 sin invisible function application A cos invisible function application B sin invisible function application C  
  3. 2 sin invisible function application A cos invisible function application B cos invisible function application C  
  4. 2 sin invisible function application A sin invisible function application B sin invisible function application C  

The correct answer is: 2 sin invisible function application A cos invisible function application B sin invisible function application C


    sin to the power of 2 end exponent invisible function application A minus sin to the power of 2 end exponent invisible function application B plus sin to the power of 2 end exponent invisible function application C equals sin invisible function application open parentheses A plus B close parentheses sin invisible function application open parentheses A minus B close parentheses plus sin to the power of 2 end exponent invisible function application C equals sin invisible function application C open parentheses sin invisible function application open parentheses A minus B close parentheses plus sin invisible function application C close parentheses
    equals sin invisible function application C open parentheses sin invisible function application open parentheses A minus B close parentheses plus sin invisible function application open parentheses A plus B close parentheses close parentheses equals 2 sin invisible function application A cos invisible function application B sin invisible function application C

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