Maths-
General
Easy

Question

In the figuretext ,  end text stack A B with bar on top divided by divided by stack C D with bar on top text  and  end text stack A C with bar on top intersection stack B D with bar on top equals 0. text  If  end text O A equals 3 x minus 1 text  , end text OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.

  1. 0    
  2. 12    
  3. 15    
  4. 18    

hintHint:

find the similar triangles and make the side ratios same and solve for x.

The correct answer is: 12


    12

    Given, CD || AB. This implies that triangles OCD and OAB are similar by angle angle angle axiom of similarity.
    (alternate angles)
    Here, < ODC = < OBA
    < OAB = <OCD
    Therefore, we can use the property that ratio of sides remains same in similar triangles.
    OA/OC= OB/OD
    =>  3x-1/5x-3 = 2x+1/6x-5
    => (3x-1)(6x-5)=(2x+1)(5x-3)
    => 18x2-21x +5 = 10x2 -x-3
    On solving we get
    2x2 -5x +2 =0
    2x2 - 4x - x + 2 = 0

    2x(x-2) -1(x-2) = 0
    (2x-1)(x-2) = 0
    either 2x -1 = 0 => x=0.5
    or x-2 = 0 => x= 2
    X= 0.5,2
    AC = OA+ OC = 3x+1 + 5x -3 = 8x – 4
    On substituting the values of x, we get
    AC = 0, 12
    Since AC can’t be 0, 12 Is the required answer.

    solving the quadratic equations by the factorization method is used. in this method, the linear term is broken down into 2 terms so that we can take out the common factors from the terms and convert the equation into product form.

    Related Questions to study

    General
    Maths-

    Two line segments text end text stack A B with rightwards arrow on top text  and  end text stack C D with bar on top text end text intersect at E such that triangle A C E tilde operator triangle B D E. If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

    We can also use trigonometry to solve this question since all the angles are same in similar triangles. Angle AEC = angle BED.

    Two line segments text end text stack A B with rightwards arrow on top text  and  end text stack C D with bar on top text end text intersect at E such that triangle A C E tilde operator triangle B D E. If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

    Maths-General

    We can also use trigonometry to solve this question since all the angles are same in similar triangles. Angle AEC = angle BED.

    General
    maths-

    From the adjacent figure ,the values of x and y are

    From the adjacent figure ,the values of x and y are

    maths-General
    General
    Maths-

    In the given figure, ABC is an Isosceles Triangle in which AB = AC, then

    we can also use trigonometry to solve this problem. For the same perpendicular distance from the vertex, the length of side increases with increase in the vertex angle since the perpendicular is the cosine component of the side.
    height = side x cos(theta). we know that cosine is a decreasing function. therefore, to keep the height same, the side has to increase.

    In the given figure, ABC is an Isosceles Triangle in which AB = AC, then

    Maths-General

    we can also use trigonometry to solve this problem. For the same perpendicular distance from the vertex, the length of side increases with increase in the vertex angle since the perpendicular is the cosine component of the side.
    height = side x cos(theta). we know that cosine is a decreasing function. therefore, to keep the height same, the side has to increase.

    parallel
    General
    maths-

    In the figure, AB = BC = CD = DE = EF and AF = AE. Then angle A = ?

    In the figure, AB = BC = CD = DE = EF and AF = AE. Then angle A = ?

    maths-General
    General
    Maths-

    In the figure, AB = AC, angle A = 48° and angle A C D = 18° . Then

    an isosceles triangle is one that has two of its sides equal and the base angles equal to each other.

    In the figure, AB = AC, angle A = 48° and angle A C D = 18° . Then

    Maths-General

    an isosceles triangle is one that has two of its sides equal and the base angles equal to each other.

    General
    Maths-

    In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of triangle A B C . Then x° + y° is

    if one of the angles were acute then we'd not have been able to conclude whether the sum of the angles were greater than or less than 180 degrees.

    In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of triangle A B C . Then x° + y° is

    Maths-General

    if one of the angles were acute then we'd not have been able to conclude whether the sum of the angles were greater than or less than 180 degrees.

    parallel
    General
    Maths-

    The perimeter of the following figure is

    perimeter is the sum of the sides of a polygon.

    The perimeter of the following figure is

    Maths-General

    perimeter is the sum of the sides of a polygon.

    General
    chemistry-

    Two pupils Ram and Shyam have taken lime water in a vessel, as shown in the figure. Ram is inhaling air from straw A and Shyam is blowing air through straw B. In which case lime water turns milky faster and Why?

    Two pupils Ram and Shyam have taken lime water in a vessel, as shown in the figure. Ram is inhaling air from straw A and Shyam is blowing air through straw B. In which case lime water turns milky faster and Why?

    chemistry-General
    General
    maths-

    If straight A equals open square brackets a subscript i j end subscript close square brackets subscript 2 cross times 2 end subscript where a subscript i j end subscript equals i plus j then A is equal to

    If straight A equals open square brackets a subscript i j end subscript close square brackets subscript 2 cross times 2 end subscript where a subscript i j end subscript equals i plus j then A is equal to

    maths-General
    parallel
    General
    Maths-

    The range of the function  f left parenthesis x right parenthesis equals square root of left parenthesis x minus 1 right parenthesis left parenthesis 3 minus x right parenthesis end root text  is  end text

    In this question, we have to find the range of f(x)=square root of open parentheses x minus 1 close parentheses open parentheses 3 minus x close parentheses end root. Here solve the function and find when function is at maximum and minimum.

    The range of the function  f left parenthesis x right parenthesis equals square root of left parenthesis x minus 1 right parenthesis left parenthesis 3 minus x right parenthesis end root text  is  end text

    Maths-General

    In this question, we have to find the range of f(x)=square root of open parentheses x minus 1 close parentheses open parentheses 3 minus x close parentheses end root. Here solve the function and find when function is at maximum and minimum.

    General
    maths-

    The range of the function  sin invisible function application open parentheses sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x close parentheses comma vertical line x vertical line less or equal than 1 text  is  end text

    The range of the function  sin invisible function application open parentheses sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x close parentheses comma vertical line x vertical line less or equal than 1 text  is  end text

    maths-General
    General
    maths-

    The domain of the function f left parenthesis x right parenthesis equals log subscript e invisible function application left parenthesis x minus left square bracket x right square bracket right parenthesis text  is  end text

    The domain of the function f left parenthesis x right parenthesis equals log subscript e invisible function application left parenthesis x minus left square bracket x right square bracket right parenthesis text  is  end text

    maths-General
    parallel
    General
    maths-

    If n element of N , and the period of fraction numerator cos invisible function application n x over denominator sin invisible function application open parentheses x over n close parentheses end fraction is 4 pi , then n is equal to

    If n element of N , and the period of fraction numerator cos invisible function application n x over denominator sin invisible function application open parentheses x over n close parentheses end fraction is 4 pi , then n is equal to

    maths-General
    General
    maths-

    Domain of definition of the function f left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x squared end fraction plus log subscript 10 invisible function application open parentheses x cubed minus x close parentheses comma text  is  end text

    Domain of definition of the function f left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x squared end fraction plus log subscript 10 invisible function application open parentheses x cubed minus x close parentheses comma text  is  end text

    maths-General
    General
    maths-

    text  If  end text f left parenthesis x right parenthesis equals open parentheses fraction numerator x over denominator 1 minus vertical line x vertical line end fraction close parentheses to the power of 1 divided by 2002 end exponent comma text  then  end text D subscript f text  is  end text

    text  If  end text f left parenthesis x right parenthesis equals open parentheses fraction numerator x over denominator 1 minus vertical line x vertical line end fraction close parentheses to the power of 1 divided by 2002 end exponent comma text  then  end text D subscript f text  is  end text

    maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.