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Easy

Question

Let $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 close curly brackets comma blank B equals left curly bracket 2 comma blank 4 comma blank 6 right curly bracket$ . Then, the number of sets $C$ such that $A intersection B subset of or equal to C subset of or equal to A blank union B$ is

6
9
8
10

The correct answer is: 8

$A intersection B equals left curly bracket 2 comma blank 4 right curly bracket$
$open curly brackets A intersection B close curly brackets subset of or equal to open curly brackets 1 comma blank 2 comma blank 4 close curly brackets comma blank open curly brackets 3 comma blank 2 comma blank 4 close curly brackets comma blank open curly brackets 6 comma blank 2 comma blank 4 close curly brackets comma blank open curly brackets 1 comma blank 3 comma blank 2 comma blank 4 close curly brackets comma$
$open curly brackets 1 comma blank 6 comma blank 2 comma blank 4 close curly brackets comma blank open curly brackets 6 comma blank 3 comma blank 2 comma blank 4 close curly brackets comma blank open curly brackets 2 comma blank 4 close curly brackets comma blank left curly bracket 1 comma blank 3 comma blank 6 comma blank 2 comma blank 4 right curly bracket subset of or equal to A union B$
$rightwards double arrow blank n open parentheses C close parentheses equals 8$

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