Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

Let $f left parenthesis x right parenthesis equals left curly bracket subscript negative x to the power of 2 end exponent minus k end subscript superscript X to the power of 2 end exponent plus k end superscript comma$ when x $greater or equal than 0$ when x $less than 0$ lf the function f(x) be continuous at x=0, then k=

0
1
2
-2

The correct answer is: 0

Related Questions to study

If the function $f left parenthesis x right parenthesis equals left curly bracket subscript 3 comma w h e n x equals fraction numerator pi over denominator 2 end fraction end subscript superscript fraction numerator k blank c o s blank x over denominator pi minus 2 x end fraction w h e n x not equal to fraction numerator pi over denominator 2 end fraction end superscript$ ’ be continuous at $chi equals fraction numerator pi over denominator 2 end fraction$ , then k=

If the function $f left parenthesis x right parenthesis equals left curly bracket subscript 3 comma w h e n x equals fraction numerator pi over denominator 2 end fraction end subscript superscript fraction numerator k blank c o s blank x over denominator pi minus 2 x end fraction w h e n x not equal to fraction numerator pi over denominator 2 end fraction end superscript$ ’ be continuous at $chi equals fraction numerator pi over denominator 2 end fraction$ , then k=

The value of $n rightwards arrow infinity vertical line i m fraction numerator 1 minus n to the power of 2 end exponent over denominator not stretchy sum subscript blank superscript blank n end fraction$ will be

The value of $n rightwards arrow infinity vertical line i m fraction numerator 1 minus n to the power of 2 end exponent over denominator not stretchy sum subscript blank superscript blank n end fraction$ will be

$n rightwards arrow infinity vertical line i m fraction numerator 1 over denominator 2 end fraction plus fraction numerator 1 over denominator 2 to the power of 2 end exponent end fraction plus fraction numerator 1 over denominator 2 to the power of 3 end exponent end fraction plus midline horizontal ellipsis plus fraction numerator 1 over denominator 2 to the power of n end exponent end fraction$ equals

$n rightwards arrow infinity vertical line i m fraction numerator 1 over denominator 2 end fraction plus fraction numerator 1 over denominator 2 to the power of 2 end exponent end fraction plus fraction numerator 1 over denominator 2 to the power of 3 end exponent end fraction plus midline horizontal ellipsis plus fraction numerator 1 over denominator 2 to the power of n end exponent end fraction$ equals

parallel

$n rightwards arrow infinity vertical line i m left square bracket fraction numerator 1 over denominator n to the power of 3 end exponent plus 1 end fraction plus fraction numerator 4 over denominator n to the power of 3 end exponent plus 1 end fraction plus fraction numerator 9 over denominator n to the power of 3 end exponent plus 1 end fraction plus midline horizontal ellipsis plus fraction numerator n to the power of 2 end exponent over denominator n to the power of 3 end exponent plus 1 end fraction right square bracket equals$

$n rightwards arrow infinity vertical line i m left square bracket fraction numerator 1 over denominator n to the power of 3 end exponent plus 1 end fraction plus fraction numerator 4 over denominator n to the power of 3 end exponent plus 1 end fraction plus fraction numerator 9 over denominator n to the power of 3 end exponent plus 1 end fraction plus midline horizontal ellipsis plus fraction numerator n to the power of 2 end exponent over denominator n to the power of 3 end exponent plus 1 end fraction right square bracket equals$

The value of $n rightwards arrow infinity vertical line i m fraction numerator chi to the power of n end exponent over denominator x to the power of n end exponent plus 1 end fraction$ where $chi less than negative 1$ is

The value of $n rightwards arrow infinity vertical line i m fraction numerator chi to the power of n end exponent over denominator x to the power of n end exponent plus 1 end fraction$ where $chi less than negative 1$ is

$S plus fraction numerator 3 over denominator 2 end fraction O subscript 2 end subscript ⟶ S O subscript 3 end subscript plus 2 x k c a l$
$S O subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction O subscript 2 end subscript ⟶ S O subscript 3 end subscript plus y k c a l$
The heat of formation of S0₂ is:

$S plus fraction numerator 3 over denominator 2 end fraction O subscript 2 end subscript ⟶ S O subscript 3 end subscript plus 2 x k c a l$
$S O subscript 2 end subscript plus fraction numerator 1 over denominator 2 end fraction O subscript 2 end subscript ⟶ S O subscript 3 end subscript plus y k c a l$
The heat of formation of S0₂ is:

Chemistry-General

parallel

One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litre. The M for this process is: (R = 2 cal K^-1 mol^-I)

One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litre. The M for this process is: (R = 2 cal K^-1 mol^-I)

Chemistry-General

In an electrochemical cell, if EO is the emf of the cell involving n mole of electrons, then is

In an electrochemical cell, if EO is the emf of the cell involving n mole of electrons, then is

Chemistry-General

Given that $capital delta H subscript f end subscript left parenthesis H right parenthesis$ = 218 kJ/mol, express the H-H bond energy in kcal/mol

Given that $capital delta H subscript f end subscript left parenthesis H right parenthesis$ = 218 kJ/mol, express the H-H bond energy in kcal/mol

Chemistry-General

parallel

The value of $x rightwards arrow 0 I i m fraction numerator 2 7 to the power of chi end exponent minus 9 to the power of chi end exponent minus 3 to the power of chi end exponent plus 1 over denominator square root of 5 minus square root of 4 plus blank c o s blank x end root end fraction$ is

The value of $x rightwards arrow 0 I i m fraction numerator 2 7 to the power of chi end exponent minus 9 to the power of chi end exponent minus 3 to the power of chi end exponent plus 1 over denominator square root of 5 minus square root of 4 plus blank c o s blank x end root end fraction$ is

$x rightwards arrow 0 I i m left square bracket fraction numerator e to the power of chi end exponent minus e to the power of blank s i n blank x end exponent over denominator x minus blank s i n blank x end fraction right square bracket$ is equal to

$x rightwards arrow 0 I i m left square bracket fraction numerator e to the power of chi end exponent minus e to the power of blank s i n blank x end exponent over denominator x minus blank s i n blank x end fraction right square bracket$ is equal to

$chi rightwards arrow infinity I i m left parenthesis 1 minus fraction numerator 4 over denominator x minus 1 end fraction right parenthesis to the power of 3 x minus 1 end exponent equals$

$chi rightwards arrow infinity I i m left parenthesis 1 minus fraction numerator 4 over denominator x minus 1 end fraction right parenthesis to the power of 3 x minus 1 end exponent equals$

parallel

lim $stack e to the power of chi end exponent minus e to the power of negative x end exponent with _ below$ is $x rightwards arrow 0$ $s vertical line n x$

lim $stack e to the power of chi end exponent minus e to the power of negative x end exponent with _ below$ is $x rightwards arrow 0$ $s vertical line n x$

$x rightwards arrow 0 I i m fraction numerator x blank t a n blank 2 x minus 2 x blank t a n blank x over denominator left parenthesis 1 minus blank c o s blank 2 x right parenthesis to the power of 2 end exponent end fraction$ is

$x rightwards arrow 0 I i m fraction numerator x blank t a n blank 2 x minus 2 x blank t a n blank x over denominator left parenthesis 1 minus blank c o s blank 2 x right parenthesis to the power of 2 end exponent end fraction$ is

$stack l i m with x rightwards arrow infinity below square root of fraction numerator x plus s i n invisible function application x over denominator x minus c o s invisible function application x end fraction end root equals$

$stack l i m with x rightwards arrow infinity below square root of fraction numerator x plus s i n invisible function application x over denominator x minus c o s invisible function application x end fraction end root equals$

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.