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stack lim with n rightwards arrow infinity below invisible function application fraction numerator 1 plus 3 plus 5 plus. blank horizontal ellipsis. plus open parentheses 2 n minus 1 close parentheses over denominator 2 plus 4 plus 6 plus. blank. blank.. plus 2 n end fraction equals

  1. 0    
  2. 1    
  3. -1    
  4. 5    

The correct answer is: 1


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