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The lengths of parallel sides of trapezium are in the ratio 7 : 5 and the distance between them is 14cm The area of trapezium is 252 cm².Find the length of its parallel sides.

21cm, 15cm
21cm, 5cm
20cm 5 cm
None

hint Hint:

We are given the ratio of parallel sides of a trapezium. The distance between them means height. The height is 14cm. The area of the trapezium is 252cm². We will use the formula of area of trapezium to find the parallel sides.

The correct answer is: 21cm, 15cm

The given quantities are as follows:
Height = 14cm
Area = 252cm²
Ratio of the sides is 7:5
Let x be the constant of proportionality of the sides.
So, if one side is 5x, the other side will be 7x.
The formula of area of trapezium is
Area = $1 half$ × sum of parallel sides × height
Substituting the values get,
252 = $1 half$ × (7x + 5x) × 14
252 = $1 half$ × 14 × 12x
252 = 7 × 12x
Dividing both the sides by 7
36 = 12x
Rearranging the equation
12x = 36
Dividing both the sides by 12 we get,
x = 3
As value of x is 3, the length of sides will be
5x = 5(3) = 15
7x = 7(3) = 21
The length of the parallel sides are 15cm and 21cm.

For such questions, we should know the formula of area of trapezium.

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The lengths of parallel sides of trapezium are in the ratio 7 : 5 and the distance between them is 14cm The area of trapezium is 252 cm².Find the length of its parallel sides.

21cm, 15cm 21cm, 5cm 20cm 5 cm None

We are given the ratio of parallel sides of a trapezium. The distance between them means height. The height is 14cm. The area of the trapezium is 252cm2. We will use the formula of area of trapezium to find the parallel sides.

The correct answer is: 21cm, 15cm

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21cm, 15cm
21cm, 5cm
20cm 5 cm
None

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AB, A₂ and B₂ are diatomic molecules. If the bond enthalpies of A₂, AB and B₂ are in the ratio 1:1:0.5 and the enthalpy of formation of AB from A₂ and B₂ – 100 kJ mol^–1, what is the bond enthalpy of A_2</sub

AB, A₂ and B₂ are diatomic molecules. If the bond enthalpies of A₂, AB and B₂ are in the ratio 1:1:0.5 and the enthalpy of formation of AB from A₂ and B₂ – 100 kJ mol^–1, what is the bond enthalpy of A_2</sub

The H – H bond energy is 430 kJ mole^–1 & Cl – Cl bond energy is 240 kJ mole^–1. ( $capital delta$ H)_ffor HClis – 90kJ. The H – Cl bond energy is about

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How many moles of electron is needed for the reduction of each mole of Cr in the reaction.
CrO₅ + H₂SO₄ $⟶$ Cr₂(SO₄)₃ + H₂O + O₂

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125 ml of Na₂CO₃ solution requires 100 ml of 0.1 N HCl to reach end point with phenolphthalein as indicator. Molarity of resulting solution with respect to $H C O subscript 3 end subscript superscript minus end superscript$ ion

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