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Maths-

General

Easy

Question

The locus of P such that PA² + PB² = 10 where A = (2, 0) and B = (4, 0) is

x² + y² + 6x + 5 = 0
x² – y² – 6x + 5 = 0
x² + y² – 6x +5 = 0
None

hint Hint:

In this question, we have to find the locus of P such that $P A squared plus P B squared equals 10$ where A = (2, 0) and B = (4, 0). A locus is a set of points, in geometry, which satisfies a given condition or situation for a shape or a figure. For we will substitute the value of A and B in the given equation and simplify it to get the required equation.

The correct answer is: x² + y² – 6x +5 = 0

$T h e space l o c u s space o f space P space i s comma space space space space P A squared plus P B squared equals 10 rightwards double arrow left parenthesis left parenthesis x minus 2 right parenthesis squared plus y to the power of 2 end exponent right parenthesis plus left parenthesis left parenthesis x minus 4 right parenthesis squared plus y to the power of 2 end exponent right parenthesis equals 10 rightwards double arrow x squared minus 4 x plus 4 plus y squared plus x squared minus 8 x plus 16 plus y squared equals 10 rightwards double arrow 2 x squared plus 2 y squared minus 12 x plus 10 equals 0 rightwards double arrow x squared plus y squared minus 6 x plus 5 equals 0$

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