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Question

The number of solution of the equationl o g subscript vertical line x minus 1 vertical line end subscript invisible function application open vertical bar x to the power of 2 end exponent minus 1 close vertical bar equals left square bracket vertical line s i n invisible function application x vertical line plus vertical line c o s invisible function application x vertical line right square bracket text  (where  end text left square bracket. right square bracketdenotes the greatest integer function) is

  1. 3    
  2. 2    
  3. 1    
  4. None of these    

The correct answer is: 1


    log subscript x minus 1 end subscript invisible function application open vertical bar x to the power of 2 end exponent minus 1 close vertical bar equals open square brackets open vertical bar sin invisible function application x close vertical bar plus open vertical bar cos invisible function application x close vertical bar close square brackets
    text Period of  end text vertical line s i n invisible function application x vertical line plus vertical line c o s invisible function application x vertical line text  is  end text fraction numerator pi over denominator 2 end fraction text  and the range of the function end text
    vertical line s i n invisible function application x vertical line plus vertical line c o s invisible function application x vertical line element of left square bracket 1 comma square root of 2 right square bracket text  then the value  end text left square bracket vertical line s i n invisible function application x vertical line plus vertical line c o s invisible function application x vertical line right square bracket equals 1
    l o g subscript 1 x minus 1 end subscript invisible function application open vertical bar x to the power of 2 end exponent minus 1 close vertical bar equals 1
    According to the definition of log,
    open vertical bar x to the power of 2 end exponent minus 1 close vertical bar not equal to 0 rightwards double arrow x not equal to plus-or-minus 1
    vertical line x minus 1 vertical line not equal to 01 rightwards double arrow x minus 1 not equal to negative 10 comma 1
    rightwards double arrow x not equal to 01 comma 2
    text So,  end text x not equal to negative 10 comma 12
    By property of log,
    open vertical bar x to the power of 2 end exponent minus 1 close vertical bar equals vertical line x minus 1 vertical line
    vertical line left parenthesis x minus 1 right parenthesis left parenthesis x plus 1 right parenthesis vertical line equals vertical line x minus 1 vertical line
    vertical line x plus 1 vertical line equals 1 left parenthesis vertical line x minus 1 vertical line not equal to 0 right parenthesis
    x plus 1 equals negative 11
    x equals negative 20
    Value n fx minus 7
    text Number of solutions is  end text 1 text  . end text

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