Question
The point which divides the line segment joint the points A(7,-6) and B(3,4) in the ratio 1:2 internally lies in the
- I quadrant
- II quadrant
- III quadrant
- IV quadrant
Hint:
A line segment in geometry has two different points on it that define its boundaries. A line segment is sometimes referred to as a section of a line that links two places. The difference between a line and a line segment is that a line has no endpoints and can go on forever in either direction. We have to find the quadrant in which the point which divides the line segment joint the points A(7,-6) and B(3,4) in the ratio 1:2 internally.
The correct answer is: III quadrant
So now we know that in a line, a line segment has two distinct endpoints. The line segment's length, which is the separation of two fixed points, is constant. The length can be calculated in feet or inches, or in metric measurements like centimetres (cm) or millimetres (mm).
Here we have given: the line segment joint the points A(7,-6) and B(3,4) in the ratio 1:2 internally
Now we know that the coordinates of the point P dividing the line segment which are joined by points A(x₁, y₁) and B(x₂, y₂) internally in the ratio m1:m2 is given by:
As given in the question, we have:
(x₁, y₁) = (7, -6)
(x₂, y₂) = (3, 4)
m₁ = 1
m₂ = 2
So, substituting the values in the equation, we get:
Here we can see that the x coordinate is positive and y coordinate is negative, so it lies in IV quadrant.
Here we used the concept of line segment and section formula, the coordinates of the point that splits a line segment (either internally or externally) into a certain ratio are found using the Section formula. Here the x coordinate is positive and y coordinate is negative, so it lies in IV quadrant.
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Two sets A and B are disjoint if and only if
If 
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.
If
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- and 
-Glucose differ in the orientation of the 
group around:
