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Maths-

General

Easy

Question

The set of values of p for which the roots of the equation 3x² +2x +p(p-1) = 0 are of opposite sign is

$(- \infty, 0)$
(0, 1)
$(1, \infty)$
$(0, \infty)$

The correct answer is: (0, 1)

Since the roots of the given equation are of opposite sign, product of the roots < 0
Þ $fraction numerator p open parentheses p minus 1 close parentheses over denominator 3 end fraction less than 0$ Þ p(p-1) < 0 Þ pÎ (0, 1).
Hence (b) is the correct answer.

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