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The value of log subscript 3 end subscript invisible function application e minus log subscript 9 end subscript invisible function application e plus log subscript 27 end subscript invisible function application e.... is equal to

  1. log subscript 3 end subscript invisible function application 2    
  2. log subscript 2 end subscript invisible function application 3    
  3. 2 log subscript 3 end subscript invisible function application 2    
  4. None of these    

The correct answer is: log subscript 3 end subscript invisible function application 2


    log subscript 3 end subscript invisible function application e minus log subscript 9 end subscript invisible function application e plus log subscript 27 end subscript invisible function application e minus....
    equals fraction numerator 1 over denominator log subscript e end subscript invisible function application 3 end fraction open square brackets 1 minus fraction numerator 1 over denominator 2 end fraction plus fraction numerator 1 over denominator 3 end fraction minus.... infinity close square brackets
    equals fraction numerator log subscript e end subscript invisible function application 2 over denominator log subscript e end subscript invisible function application 3 end fraction equals log subscript 3 end subscript invisible function application 2

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