Maths-
General
Easy
Question
There are (n + 1) white and (n + 1) black balls each set numbered 1 to (n + 1). The number of ways in which the balls can be arranged in row so that the adjacent balls are of different colours is- - (2n + 2)!
- (2n + 2)! × 2
- (n + 1)! × 2
- 2{(n + 1)!}2
- (2n + 2)!
- (2n + 2)! × 2
- (n + 1)! × 2
- 2{(n + 1)!}2
The correct answer is: 2{(n + 1)!}2
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