What is the size of the class?

Hence option 3 is corrrect

In a Parallelogram the diagonals intersect at O. If $O A equals 2 x plus 15 comma O C equals 10 x minus 9$ then AC is

Hence option 4 is correct

In a Parallelogram the diagonals intersect at O. If $O A equals 2 x plus 15 comma O C equals 10 x minus 9$ then AC is

Hence option 4 is correct

PQRS is a Quadrilateral in which

So here we used the concept of a quadrilateral to understand the question. It is basically 4 sided shape that can take any figure. We also used the angle sum property of a quadrilateral which is 360 degrees. So here the angle R + S is 180 degrees.

PQRS is a Quadrilateral in which

ABCD is a Quadrilateral in which

The diagonals of a Rectangle ABCD meet at O. If $angle B O C equals 44 to the power of ring operator end exponent blank t h e n blank angle O A D equals$

Hence option 2 is correct

The diagonals of a Rectangle ABCD meet at O. If $angle B O C equals 44 to the power of ring operator end exponent blank t h e n blank angle O A D equals$

Hence option 2 is correct

A Square of side 4 units is combined with two right angled triangles of bases each 3units to form a Trapezium (as shown in figure). Then perimeter of the Trapezium is

Therefore, the perimeter of trapezium is 24 units.

A Square of side 4 units is combined with two right angled triangles of bases each 3units to form a Trapezium (as shown in figure). Then perimeter of the Trapezium is

Therefore, the perimeter of trapezium is 24 units.

In the figure, ABCD is a kite with AB = AD, BC = CD and $stack A C with bar on top blank i n t e r s e c t s blank stack B D with bar on top blank a t$ O. If $angle O A B equals 25 to the power of ring operator end exponent blank a n d blank angle O D C equals 50 to the power of ring operator end exponent$ then a – b + c – d + e – f =

Area of square field is $1 fraction numerator 17 over denominator 64 end fraction c m to the power of 2 end exponent$ . The length of each side is

Hence option 3 is correct

Area of square field is $1 fraction numerator 17 over denominator 64 end fraction c m to the power of 2 end exponent$ . The length of each side is

Hence option 3 is correct

The cube root of 110592 is

Hence option 4 is correct

The cube root of 110592 is

Hence option 4 is correct

In a Quadrilateral ABCD, bisectors of $angle A blank a n d blank angle B$ meet at a point P. If $angle C equals$ 100º and $angle D equals 50 to the power of ring operator end exponent$ then measure of $angle A P B equals ?$

Hence option 2 is correct

In a Quadrilateral ABCD, bisectors of $angle A blank a n d blank angle B$ meet at a point P. If $angle C equals$ 100º and $angle D equals 50 to the power of ring operator end exponent$ then measure of $angle A P B equals ?$

Hence option 2 is correct

The side $stack B C with bar on top$ of an equilateral triangle ABC is trisected at (D) Then $A D to the power of 2 end exponent equals horizontal ellipsis.. cross times A B to the power of 2 end exponent$

In the figure, $stack D E with bar on top divided by divided by stack B C with bar on top blank a n d blank a r blank left parenthesis triangle A D E right parenthesis equals a r invisible function application left parenthesis capital delta B E left parenthesis D right parenthesis.$ The value of $fraction numerator B D over denominator A B end fraction equals ?$