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Physics-

General

Easy

Question

A ball is dropped from a high rise platform at $t equals 0$ starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed $v$ . The two balls meet at $t equals 18 s$ . What is the value of $v$ ? (taking $g equals 10 blank m divided by s to the power of 2 end exponent$ )

$60 m / s$
$75 m / s$
$55 m / s$
$40 m / s$

The correct answer is: $75 blank m divided by s$

Let two balls meet at depth $h$ from platform
So $h equals fraction numerator 1 over denominator 2 end fraction g open parentheses 18 close parentheses to the power of 2 end exponent equals v open parentheses 12 close parentheses plus fraction numerator 1 over denominator 2 end fraction g open parentheses 12 close parentheses to the power of 2 end exponent rightwards double arrow v equals 75 blank m s to the power of negative 1 end exponent$

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$open parentheses g equals 10 blank m s to the power of negative 2 end exponent close parentheses$

A balloon gong upward with a velocity of $12 blank m s to the power of negative 1 end exponent$ is at a height of 65 m from the earth’s surface at any instant. Exactly at this instant a ball drops from it. How much time will the ball take in reaching the surface of earth?
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A bullet fired into a fixed target loses half of its velocity after penetrating $3 blank c m$ . How much further it will penetrate before coming to rest assuming that if faces constant resistance to motion

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Physics-General

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