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Question

ball is suspended from the top of a cart by a light string of length1.0 m. The cart and the ball are initially moving to the right at constant speed V, as shown in figure I. The cart comes to rest after colliding and sticking to a fixed bumper, as in figure II. The suspended ball swings through a maximum angle 60°.The initial speed V is (take g = 10 m/s2) (neglect friction)

  1. square root of 10 m divided by s    
  2. 2 square root of 5 m divided by s    
  3. 5 square root of 2 m divided by s    
  4. 4 m divided by s    

The correct answer is: square root of 10 m divided by s


    As string does no work on the ball, energy conservation can be applied.
    fraction numerator 1 over denominator 2 end fraction m V to the power of 2 end exponent equals m g left parenthesis L minus L c o s invisible function application theta right parenthesis rightwards double arrow V equals square root of 2 g L left parenthesis 1 minus c o s invisible function application theta right parenthesis end root
    on putting valuesV equals square root of 10 m divided by s

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