Physics-
General
Easy

Question

A body falling for 2 seconds covers a distance S blankis equal to that covered in next second. Taking g equals 10 m divided by s to the power of 2 end exponent,blank S equals

  1. 30 blank m  
  2. 10 m  
  3. 60blank m  
  4. 20m  

The correct answer is: 30 blank m


    If u is the initial velocity then distance covered by it in 2 blank s e c
    S equals u t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent equals u cross times 2 plus fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 4 equals 2 u plus 20 blank left parenthesis i right parenthesis
    Now distance covered by it in 3rds e c
    S subscript 3 to the power of r d end exponent end subscript equals u plus fraction numerator 1 over denominator 2 end fraction open parentheses 2 cross times 3 minus 1 close parentheses 10 equals u plus 25 blank left parenthesis i i right parenthesis
    From (i) and (ii), 2 u plus 20 equals u plus 25 rightwards double arrow u equals 5
    therefore S equals 2 cross times 5 plus 20 equals 30 blank m

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