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Physics-

General

Easy

Question

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

$2 v^{2} / π r$
$2 \sqrt{2} v^{2} / π r$
$v^{2} / π r$
None of these

The correct answer is: $2 square root of 2 v to the power of 2 end exponent divided by pi r$

Here, $T equals fraction numerator 2 pi r over denominator 4 v end fraction equals fraction numerator pi r over denominator 2 v end fraction$
Change in velocity is going from $A$ to $B$ = $v square root of 2$
Average acceleration $equals fraction numerator v square root of 2 over denominator pi r divided by 2 v end fraction equals fraction numerator 2 square root of 2 v to the power of 2 end exponent over denominator pi r end fraction$

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