Physics-
General
Easy
Question
A capacitor of capacitance C is connected to a cell of emf V and when fully charged, it is disconnected. Now the separation between the plates is doubled. The change in flux of electric field through a closed surface enclosing the capacitor is
- Zero
The correct answer is: Zero
Flux = 
The two plates of the capacitor have equal and opposite charges.
Hence, net charge enclosed by the given surface = 0
Flux is zero in both cases.
Hence change in flux = 0
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