Physics-
General
Easy

Question

A flexible wire bent in the form of a circle is placed in a uniform magnetic field perpendicular to the plane of the coil. The radius of the coil changes as shown in figure. The graph of induced emf in the coil is represented by

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The correct answer is:


    phi equals B A equals B cross times pi r to the power of 2 end exponent
    therefore phi proportional to r to the power of 2 end exponent rightwards double arrow phi equals k r to the power of 2 end exponent (k = constant)
    therefore e equals fraction numerator d phi over denominator d t end fraction equals k.2 r fraction numerator d r over denominator d t end fraction
    From 0 – 1, r is constant, \fraction numerator d r over denominator d t end fraction equals 0 hence, e = 0
    From 1 – 2, r equals alpha t comma \fraction numerator d r over denominator d t end fraction equals alpha hence e proportional to r Þ e proportional to t
    From 2 – 3, again r is constant, \fraction numerator d r over denominator d t end fraction equals 0hence e = 0

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