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Physics-

General

Easy

Question

A junction diode is connected to a 10 V source and $10 to the power of 3 end exponent capital omega$ rheostate figure. The slope of load line on the characteristic curve of diode will be

$10^{- 2} A V^{- 1}$
$10^{- 3} A V^{- 1}$
$10^{- 4} A V^{- 1}$
$10^{- 5} A V^{- 1}$

The correct answer is: $10 to the power of negative 3 end exponent A V to the power of negative 1 end exponent$

If $V$ is the voltage across the junction and $I$ is the circuit current, then
$V plus I R equals E$
or $I equals fraction numerator E over denominator R end fraction minus fraction numerator V over denominator R end fraction equals negative fraction numerator V over denominator R end fraction plus fraction numerator E over denominator R end fraction$
Slope of load line $blank equals negative fraction numerator 1 over denominator R end fraction equals fraction numerator 1 over denominator 1000 end fraction equals 10 to the power of negative 3 end exponent A V to the power of negative 1 end exponent.$

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