Physics-
General
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Question

A man drops a ball downside from the roof of a tower of height 400 blank m. At the same time another ball is thrown upside with a velocity 50 blank m divided by s. From the surface of the tower, then they will meet at which height from the surface of the tower

  1. 100 blank m  
  2. 320 blank m  
  3. 80 blank m  
  4. 240 blank m  

The correct answer is: 80 blank m


    Let both balls meet at point P after time t

    The distance travelled by ball A comma blank h subscript 1 end subscript equals fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
    The distance travelled by ball B comma blank h subscript 2 end subscript equals u t minus fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
    h subscript 1 end subscript plus h subscript 2 end subscript equals 400 blank m blank rightwards double arrow u t equals 400 comma blank t equals 400 divided by 50 equals 8 blank s e c
    therefore h subscript 1 end subscript equals 320 m and h subscript 2 end subscript equals 80 blank m

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