Physics-
General
Easy

Question

A particle is projected up with an initial velocity of 80 blank f t divided by s e c. The ball will be at a height of 96 blank f t from the ground after

  1. 2.0 and 3.0 blank s e c  
  2. Only at 3.0 blank s e c  
  3. Only at 2.0 blank s e c  
  4. After 1 and 2 blank s e c  

The correct answer is: 2.0 and 3.0 blank s e c


    h equals u t minus fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent rightwards double arrow 96 equals 80 t minus fraction numerator 32 over denominator 2 end fraction t to the power of 2 end exponent
    rightwards double arrow t to the power of 2 end exponent minus 5 t plus 6 equals 0 rightwards double arrow t equals 2 s e c or 3 blank s e c

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