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Physics

General

Easy

Question

A particle is thrown in upward direction with initial velocity V_⁰ It crosses point P at height h at time t₁ and t₂ so t₁ t₂ ……..

$\frac{2 h}{B}$
$\frac{V_{0}}{2 g}$
$\frac{2 V_{0}}{g}$
$\frac{h}{2 g}$

The correct answer is: $fraction numerator 2 h over denominator B end fraction$

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$2.1 squared plus 3.2 squared plus 4.3 squared plus midline horizontal ellipsis horizontal ellipsis plus left parenthesis n plus 1 right parenthesis n squared equals$

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The domain of the function $f left parenthesis x right parenthesis equals fraction numerator tan invisible function application 2 x over denominator 6 cos invisible function application x plus 2 sin invisible function application 2 x end fraction text is end text$

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If $f left parenthesis x right parenthesis equals fraction numerator 10 to the power of x minus 10 to the power of negative x end exponent over denominator 10 to the power of x plus 10 to the power of negative x end exponent end fraction text then end text f to the power of negative 1 end exponent left parenthesis x right parenthesis equals$

If $f left parenthesis x right parenthesis equals fraction numerator 10 to the power of x minus 10 to the power of negative x end exponent over denominator 10 to the power of x plus 10 to the power of negative x end exponent end fraction text then end text f to the power of negative 1 end exponent left parenthesis x right parenthesis equals$

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$text II) end text d f equals 2.1$
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The true statements are

If $f left parenthesis x right parenthesis equals x squared plus x comma x equals 10 comma delta x equals 0.1$ observe the following
$text l) end text delta f equals 2.11$
$text II) end text d f equals 2.1$
$text III) Relative error in end text x text is end text 1$
The true statements are

parallel

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