Physics-
General
Easy

Question

A particle of mass m moving with velocity u makes an elastic one dimensional collision with a stationary particle of mass m. They are in contact for a very short time T. Their force of interaction increases from zero to F0 linearly in time T/2, and decreases linearly to zero in further time T/2. The magnitude of F0 is

  1. m u divided by T    
  2. 2 m u divided by T    
  3. m u divided by 2 T    
  4. None of these    

The correct answer is: 2 m u divided by T


    In elastic one dimensional collision particle rebounds with same speed in opposite direction
    i.e. change in momentum equals 2 m u
    But Impulse equals F cross times T equalsChange in momentum
    Þ F subscript 0 end subscript cross times T equals 2 m uÞ F subscript 0 end subscript equals fraction numerator 2 m u over denominator T end fraction

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