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Physics-

General

Easy

Question

A particle starts from rest at $t equals 0$ and undergoes an acceleration $a$ in $m s to the power of negative 2 end exponent$ with time $t$ in second which is as shownWhich one of the following plot represents velocity $v$ in $m s to the power of negative 1 end exponent blank v e r s u s$ time $t$ in second?

The correct answer is:

A particle starts from rest at $t equals 0$
The equation of motion
$v equals u plus a t equals 0 plus 3 cross times 2 equals 6 blank m s to the power of negative 1 end exponent$
The velocity for next 2 s
$v to the power of ´ end exponent equals v plus a t$
$blank equals 6 minus 3 cross times 2 equals 0$
$v to the power of ´ end exponent equals 0$

Hence, $v minus t$ graph will be as shown.

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