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Physics

Mechanics

Easy

Question

$A space p r o j e c t i l e space o f space m a s s space m space i s space t h r o w n space w i t h space v e l o c i t y space v space m a k i n g space a n space a n g l e space o f space 30 degree space w i t h space v e r t i c a l. space N e g l e c t i n g space a i r space r e s i s tan c e space t h e space m a g n i t u d e space o f space c h a n g e space i n space m o m e n t u m space b e t w e e n space t h e space s t a r t i n g space p o i n t space a n d space a t space t h e space m a x i m u m space h e i g h t space i s space$

$\frac{m v}{2}$
$\frac{\sqrt{3} m v}{2}$
$m v$
$\frac{\sqrt{7} m v}{2}$

The correct answer is: $fraction numerator square root of 3 m v over denominator 2 end fraction$

$table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell v with not stretchy rightwards arrow on top subscript i equals u cos invisible function application theta i with not stretchy hat on top plus u sin invisible function application theta j with not stretchy hat on top end cell row cell v with not stretchy rightwards arrow on top subscript f equals u cos invisible function application theta i with not stretchy hat on top end cell row cell straight capital delta p with not stretchy rightwards arrow on top equals m open parentheses v with not stretchy rightwards arrow on top subscript f minus v with not stretchy rightwards arrow on top subscript i close parentheses end cell row cell straight capital delta p with not stretchy rightwards arrow on top equals negative m u sin invisible function application theta j with not stretchy hat on top end cell row cell vertical line straight capital delta p with not stretchy rightwards arrow on top vertical line equals m u sin invisible function application 60 to the power of ring operator equals fraction numerator square root of 3 m u over denominator 2 end fraction end cell end table$

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