Physics-
General
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Question

A ring of mass 100 kg and diameter 2m is rotating at the rate of open parentheses fraction numerator 300 over denominator pi end fraction close parenthesesrpm. Then-

  1. moment of inertia is 100 kg – m2  
  2. kinetic energy is 5 kJ  
  3. if a retarding torque of 200 N-m starts acting then it will come at rest after 5 sec.  
  4. all of these  

The correct answer is: all of these


    Moment of inertia = MR2
    k.E of rotation = fraction numerator 1 over denominator 2 end fractionI2
    Torque = I where  = fraction numerator omega subscript 0 end subscript over denominator t end fraction

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