Physics-
General
Easy

Question

A source producing sound of frequency 170 Hz is approaching a stationary observer with a velocity 17 ms–1. The apparent change in the wavelength of sound heard by the observer is (speed of sound in air = 340 ms–1)

  1. 0.1m    
  2. 0.2m    
  3. 0.4m    
  4. 0.5m    

The correct answer is: 0.1m


    lambda equals fraction numerator v over denominator n end fraction equals fraction numerator 340 over denominator 170 end fraction equals 2 m comma n ´ equals fraction numerator 340 over denominator 340 minus 17 end fraction cross times 170 rightwards double arrow n ´ equals 178.9 H z
    Now lambda to the power of ´ end exponent equals fraction numerator v over denominator n to the power of ´ end exponent end fraction equals fraction numerator 340 over denominator 178.9 end fraction equals 1.9
    Þ lambda minus lambda to the power of ´ end exponent equals 2 minus 1.9 equals 0.1

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