Physics-
General
Easy

Question

A square loop of side 5 cm enters a magnetic field with 1 cms-1. The front edge enters the magnetic field at t = 0 then which graph best depicts emf

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The correct answer is:


    When loop is entering in the field, magnetic flux (i.e. ´) linked with the loop increases so induced emf in it e equals B v l =0.6 cross times 1 0 to the power of negative 2 end exponent cross times 5 cross times 1 0 to the power of negative 2 end exponent equals 3 cross times 1 0 to the power of negative 4 end exponent V (Negative) .
    When loop completely entered in the field (after 5 sec) flux linked with the loop remains constant so e = 0.
    After 15 sec, loop begins to exit out, linked magnetic flux decreases so induced emf e equals 3 cross times 1 0 to the power of negative 4 end exponent V (Positive).

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