Question
A string has a linear mass density ' ' μ and a length L = 3m. Its two ends are D =2m apart. Two blocks of mass 
each are suspended from the string as shown in the figure. The time taken by a wave pulse to travel from point A to point B is
The correct answer is:
Related Questions to study
The displacement y of a particle executing periodic motion is given by .
This expression may be considered to be a result of the superposition of waves :
The displacement y of a particle executing periodic motion is given by . This expression may be considered to be a result of the superposition of waves :
A transverse sinusoidal wave moves along a string in the positive x–direction at a speed of 10 cm/s. The wavelength of the wave is 0.5 m and its amplitude is 10 cm. At a particular time t, the snap–shot of the wave is shown in figure. The velocity of point P when its displacement is 5 cm is
A transverse sinusoidal wave moves along a string in the positive x–direction at a speed of 10 cm/s. The wavelength of the wave is 0.5 m and its amplitude is 10 cm. At a particular time t, the snap–shot of the wave is shown in figure. The velocity of point P when its displacement is 5 cm is
The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1 = A sin 
sin ωt and energy is E1 and in other experiment its displacement 
and energy is E2
The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1 = A sin sin ωt and energy is E1 and in other experiment its displacement and energy is E2
S1 and S2 are two coherent currents sources of radiations separated by distance 100.25 λ , where l is the wave length of radiation. S1 leads S2 in phase by Π/ 2 . A and B are two points on the line joining S1 and S2 as shown in figure. The ratio of amplitudes of sources S1 and S2 are in the ratio 1 : 2. The ratio of intensity at A to that of B 
is
S1 and S2 are two coherent currents sources of radiations separated by distance 100.25 λ , where l is the wave length of radiation. S1 leads S2 in phase by Π/ 2 . A and B are two points on the line joining S1 and S2 as shown in figure. The ratio of amplitudes of sources S1 and S2 are in the ratio 1 : 2. The ratio of intensity at A to that of B is
The amplitude of a wave disturbance propagating in the positive x–direction is given by y= 
at t= 0 and 
t = 2s, where x and y are in meter. Assuming that the shape of the wave disturbance does not change during the propagation, the speed of the wave is
The amplitude of a wave disturbance propagating in the positive x–direction is given by y= at t= 0 and t = 2s, where x and y are in meter. Assuming that the shape of the wave disturbance does not change during the propagation, the speed of the wave is
Statement-1 : Two sound waves of equal intensity I produced beats. The maximum intensity of sound produced in beats is 4I
Statement-2 : If two waves of amplitudes a1 and a2 superpose, the maximum amplitude of the resultant wave = a1 + a2
Statement-1 : Two sound waves of equal intensity I produced beats. The maximum intensity of sound produced in beats is 4I
Statement-2 : If two waves of amplitudes a1 and a2 superpose, the maximum amplitude of the resultant wave = a1 + a2
Statement – 1: Two tuning forks having frequency 410 Hz and 524 Hz are kept close and made to vibrate. Beats will not be heard
Statement – 2 : Sound waves superimpose only when the frequencies of superposing waves are equal or nearly equal
Statement – 1: Two tuning forks having frequency 410 Hz and 524 Hz are kept close and made to vibrate. Beats will not be heard
Statement – 2 : Sound waves superimpose only when the frequencies of superposing waves are equal or nearly equal
Statement – 1: In case of beats, intensity of sound at some positions in space remains maximum and at others, it remains minimum
Statement – 2: Beat are formed due to superposition of sound waves of unequal frequencies
Statement – 1: In case of beats, intensity of sound at some positions in space remains maximum and at others, it remains minimum
Statement – 2: Beat are formed due to superposition of sound waves of unequal frequencies
STATEMENT – 1 : In the case of stationary wave, a person hear a loud sound at the nodes as compared to the antinodes. Because
STATEMENT – 2 : In a stationary wave all the particles of the medium vibrate in phase
STATEMENT – 1 : In the case of stationary wave, a person hear a loud sound at the nodes as compared to the antinodes. Because
STATEMENT – 2 : In a stationary wave all the particles of the medium vibrate in phase
STATEMENT – 1 : When standing waves are produced in a closed organ pipe, the pressure at the closed end is a constant. Because
STATEMENT – 2 : The closed end corresponds to a node and hence the pressure is constant
STATEMENT – 1 : When standing waves are produced in a closed organ pipe, the pressure at the closed end is a constant. Because
STATEMENT – 2 : The closed end corresponds to a node and hence the pressure is constant
STATEMENT – 1 : Soldiers are asked to break steps while crossing the bridge to avoid resonance situation. Because
STATEMENT – 2 : When frequency of two oscillating system are equal, their amplitude of vibration become very high
STATEMENT – 1 : Soldiers are asked to break steps while crossing the bridge to avoid resonance situation. Because
STATEMENT – 2 : When frequency of two oscillating system are equal, their amplitude of vibration become very high
STATEMENT – 1 : If an observer places his ear at the end of a long steel pipe, he can hear two distinct sounds, when a workman hammers the other end of the pipe. Because
STATEMENT – 2 : Longitudinal as well as transverses wave can be propagated in steel
STATEMENT – 1 : If an observer places his ear at the end of a long steel pipe, he can hear two distinct sounds, when a workman hammers the other end of the pipe. Because
STATEMENT – 2 : Longitudinal as well as transverses wave can be propagated in steel
STATEMENT – 1 :speed of sound in air was found wrong because, he assumed process as isothermal. Because
STATEMENT – 2 : Flow of sound wave in a medium is very fast. Quick process suppress heat exchange, hence this process must be adiabatic in nature
STATEMENT – 1 :speed of sound in air was found wrong because, he assumed process as isothermal. Because
STATEMENT – 2 : Flow of sound wave in a medium is very fast. Quick process suppress heat exchange, hence this process must be adiabatic in nature
STATEMENT – 1 : The velocity of sound in air, at constant temperature, does not depend on the ambient pressure. Because
STATEMENT – 2 : This is a consequence of the fact that the velocity of sound is a function of the ratio p/p but as P increases, 
increases by the same factor at constant temperature
STATEMENT – 1 : The velocity of sound in air, at constant temperature, does not depend on the ambient pressure. Because
STATEMENT – 2 : This is a consequence of the fact that the velocity of sound is a function of the ratio p/p but as P increases, increases by the same factor at constant temperature
STATEMENT – 1 : The basic of Laplace correction was the exchange of heat between the region of compression and rarefaction in air is not possible. Because
STATEMENT – 2 : Air is a bad conductor of heat and velocity of sound in air is large
STATEMENT – 1 : The basic of Laplace correction was the exchange of heat between the region of compression and rarefaction in air is not possible. Because
STATEMENT – 2 : Air is a bad conductor of heat and velocity of sound in air is large
