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Physics

Mechanics

Easy

Question

A uniform circular disc of radius 'R' lies in the X-Y plane with the centre coinciding with the origin. The moment of inertia about an axis passing through a point on the X-axis at a distance x = 2R and perpendicular to the X-Y plane is equal to its moment of inertia about an axis passing through a point on the Y-axis at a distance y = d and parallel to the X-axis in the X-Y plane. The value of 'd' is

$\frac{4 R}{3}$
$\sqrt{17} (\frac{R}{2})$
$\sqrt{15} (\frac{R}{2})$
$\sqrt{13} (\frac{R}{2})$

The correct answer is: $square root of 17 open parentheses R over 2 close parentheses$

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