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Physics

Mechanics

Easy

Question

A wheel of moment of inertia $2.0 cross times 10 cubed kgm squared$ is rotating at uniform angular speed of $4 rads to the power of negative 1 end exponent$ . What is the torque required to stop it in one second.

$0.5 \times 10^{3} Nm$
$8.0 \times 10^{3} Nm$
$2.0 \times 10^{3} Nm$
none of these

The correct answer is: $8.0 cross times 10 cubed Nm$

$alpha equals omega over t equals 4 over 1 equals 4 rad divided by straight s squared$

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