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Question

An aircraft with a wing-span of 40 m flies with a speed of 1080 km h–1 in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of earth's magnetic field is 1.75 cross times 10–5 T. Then the emf that develops between the tips of the wings is

  1. 0.5 V    
  2. 0.35 V    
  3. 0.21 V    
  4. 2.1 V    

The correct answer is: 0.21 V


    L=40 m, v =1080km h–1 =300m sec–1 and B =1.75 ´ 10–5 T Þ e equals B l v equals 1.75 cross times 1 0 to the power of negative 5 end exponent cross times 40 cross times 300 equals 0.21 V

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