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Question

An inductor left parenthesis L equals 100 blank m H right parenthesis, a resistor left parenthesis R equals 100 capital omega right parenthesis and a battery left parenthesis E equals 100 V right parenthesis are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit 1 blank m s after the short circuit is

  1. e blank A  
  2. 0.1 blank A  
  3. 1 blank A  
  4. 1 divided by e blank A  

The correct answer is: 1 divided by e blank A


    During decay of current
    i equals i subscript 0 end subscript e to the power of negative fraction numerator R t over denominator L end fraction end exponent equals fraction numerator E over denominator R end fraction e to the power of negative fraction numerator R t over denominator L end fraction end exponent equals fraction numerator 100 over denominator 100 end fraction e to the power of negative fraction numerator 100 cross times 10 to the power of negative 3 end exponent over denominator 100 cross times 10 to the power of negative 3 end exponent end fraction end exponent equals fraction numerator 1 over denominator e end fraction A

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