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Question

Block A weighing 100 kg rests on a block B and is tied with a horizontal string to the wall at C. Block B weighs 200 kg. The coefficient of friction between A and B is 0.25 and between B and the surface is 1/3. The horizontal force P necessary to move the block B should be left parenthesis g equals 10 m divided by s to the power of 2 end exponent right parenthesis

  1. 1150 N    
  2. 1250 N    
  3. 1300 N    
  4. 1420 N    

The correct answer is: 1250 N


    Friction between block A and block B & between block B and surface will oppose the P
    therefore P equals F subscript A B end subscript plus F subscript B S end subscript equals mu subscript A B end subscript m subscript A end subscript g plus mu subscript B S end subscript left parenthesis m subscript A end subscript plus m subscript B end subscript right parenthesis g
    equals 0.25 cross times 100 cross times 10 plus fraction numerator 1 over denominator 3 end fraction left parenthesis 100 plus 200 right parenthesis cross times 10=1250 N

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