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Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube. K shell electrons of tungsten have ionization energy 72.5 keV. X-rays emitted by the tube contain only

  1. A continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of ~ 0.155Å    
  2. A continuous X-ray spectrum (Bremsstrahlung] with all wavelengths    
  3. The characteristic X-rays spectrum of tungsten    
  4. A continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of ~ 0.155Å and the characteristic X-ray spectrum of tungsten    

The correct answer is: A continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of ~ 0.155Å and the characteristic X-ray spectrum of tungsten


    Minimum wavelength of continuous X-ray spectrum is given by lambda fraction numerator 12375 over denominator E left parenthesis e V right parenthesis end fraction fraction numerator 12375 over denominator 80 cross times 1 0 to the power of 3 end exponent end fraction subscript m i n end subscript
    Also the energy of the incident electrons (80 KeV) is more than the ionization energy of the K-shell electrons (i.e. 72.5 KeV). Therefore characteristic X-ray spectrum will also be obtained because energy of incident electron is enough to knock out the electron from K or L shells

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