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Chemistry-

General

Easy

Question

Extraction of zinc from zinc blende is achieved by-

electrolytic reduction
roasting followed by reduction with carbon
roasting followed by reduction with another metal
roasting followed by self-reduction

The correct answer is: roasting followed by reduction with carbon

Related Questions to study

When the sample of Cu with Zn impurity is to be purified by electrolysis, the appropriate electrodes are-
CathodeAnode

When the sample of Cu with Zn impurity is to be purified by electrolysis, the appropriate electrodes are-
CathodeAnode

Chemistry-General

Which statement is not correct for Kohlrausch law?

Which statement is not correct for Kohlrausch law?

Chemistry-General

The equivalent conductivity of 0.1 M weak acid is 100 times less than that at infinite dilution. The degree of dissociation of weak electrolyte at 0.1 M is –

The equivalent conductivity of 0.1 M weak acid is 100 times less than that at infinite dilution. The degree of dissociation of weak electrolyte at 0.1 M is –

Chemistry-General

parallel

3 faraday of electricity are passed through molten Al₂O₃, aqueous solution of CuSO₄ and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of –

3 faraday of electricity are passed through molten Al₂O₃, aqueous solution of CuSO₄ and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of –

Chemistry-General

Beryllium is placed above magnesium in the II group. Beryllium dust, therefore, when added to MgCl₂ solution will –

Beryllium is placed above magnesium in the II group. Beryllium dust, therefore, when added to MgCl₂ solution will –

Chemistry-General

Metals can be prevented from rusting by –

Metals can be prevented from rusting by –

Chemistry-General

parallel

The thermodynamic efficiency of cell is given by –

The thermodynamic efficiency of cell is given by –

Chemistry-General

The following facts are available $table row cell 2 X to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow 2 Y to the power of minus end exponent plus X subscript 2 end subscript end cell row cell 2 W to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow text end text text N end text text o end text text end text text r end text text e end text text a end text text c end text text t end text text i end text text o end text text n end text text end text end cell row cell 2 Z to the power of minus end exponent plus X subscript 2 end subscript rightwards arrow 2 X to the power of minus end exponent plus Z subscript 2 end subscript end cell end table$ Which of the following is correct?

The following facts are available $table row cell 2 X to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow 2 Y to the power of minus end exponent plus X subscript 2 end subscript end cell row cell 2 W to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow text end text text N end text text o end text text end text text r end text text e end text text a end text text c end text text t end text text i end text text o end text text n end text text end text end cell row cell 2 Z to the power of minus end exponent plus X subscript 2 end subscript rightwards arrow 2 X to the power of minus end exponent plus Z subscript 2 end subscript end cell end table$ Which of the following is correct?

Chemistry-General

A standard hydrogen electrode has zero electrode potential because:

A standard hydrogen electrode has zero electrode potential because:

Chemistry-General

parallel

Given that $E subscript F e to the power of 3 plus end exponent divided by F e to the power of 2 plus end exponent end subscript equals negative 0.36 V$ and $E subscript F e to the power of 2 plus end exponent divided by F e end subscript equals negative 0.439 V$ respectively. Therefore value of $E to the power of ring operator end exponent F e to the power of 3 plus end exponent comma F e to the power of 2 plus end exponent divided by P t$ is :

Given that $E subscript F e to the power of 3 plus end exponent divided by F e to the power of 2 plus end exponent end subscript equals negative 0.36 V$ and $E subscript F e to the power of 2 plus end exponent divided by F e end subscript equals negative 0.439 V$ respectively. Therefore value of $E to the power of ring operator end exponent F e to the power of 3 plus end exponent comma F e to the power of 2 plus end exponent divided by P t$ is :

Chemistry-General

Given that $E subscript H subscript 2 end subscript O open vertical bar H subscript 2 end subscript close vertical bar P t end subscript equals 0$ at 298 K. The pressure of H₂(g) would be –

Given that $E subscript H subscript 2 end subscript O open vertical bar H subscript 2 end subscript close vertical bar P t end subscript equals 0$ at 298 K. The pressure of H₂(g) would be –

Chemistry-General

Two half cells have reduction potentials –0.76 V and – 0.13 V respectively. A galvanic cell is made from these two half cells. Which of the following statements is correct?

Two half cells have reduction potentials –0.76 V and – 0.13 V respectively. A galvanic cell is made from these two half cells. Which of the following statements is correct?

Chemistry-General

parallel

Given that Eº values of Ag⁺/Ag, K⁺/ K, Mg²⁺/ Mg and Cr³⁺/ Cr are 0.80V, –2.93V, –2.37V and –0.74V respectively. Therefore, the order for the reducing power of the metal is -

Given that Eº values of Ag⁺/Ag, K⁺/ K, Mg²⁺/ Mg and Cr³⁺/ Cr are 0.80V, –2.93V, –2.37V and –0.74V respectively. Therefore, the order for the reducing power of the metal is -

Chemistry-General

The standard potentials at 298 K for the following half reactions are as given
$table row cell Z n to the power of 2 plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon Z n left parenthesis s right parenthesis semicolon minus 0.762 V end cell row cell C r to the power of 3 plus end exponent left parenthesis a q right parenthesis plus 3 e to the power of minus end exponent rightwards harpoon over leftwards harpoon C r left parenthesis s right parenthesis semicolon minus 0.74 V end cell row cell 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon H subscript 2 end subscript left parenthesis g right parenthesis semicolon plus 0.00 V end cell row cell F e to the power of 3 plus end exponent left parenthesis a q right parenthesis plus e to the power of minus end exponent rightwards harpoon over leftwards harpoon F e to the power of 2 plus end exponent left parenthesis a q right parenthesis semicolon plus 0.77 V end cell end table$
Which of the following is the strongest reducing agent?

The standard potentials at 298 K for the following half reactions are as given
$table row cell Z n to the power of 2 plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon Z n left parenthesis s right parenthesis semicolon minus 0.762 V end cell row cell C r to the power of 3 plus end exponent left parenthesis a q right parenthesis plus 3 e to the power of minus end exponent rightwards harpoon over leftwards harpoon C r left parenthesis s right parenthesis semicolon minus 0.74 V end cell row cell 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon H subscript 2 end subscript left parenthesis g right parenthesis semicolon plus 0.00 V end cell row cell F e to the power of 3 plus end exponent left parenthesis a q right parenthesis plus e to the power of minus end exponent rightwards harpoon over leftwards harpoon F e to the power of 2 plus end exponent left parenthesis a q right parenthesis semicolon plus 0.77 V end cell end table$
Which of the following is the strongest reducing agent?

Chemistry-General

In which of the following is the cell the overall cell reaction is: $Z n plus H subscript 2 end subscript S O subscript 4 end subscript rightwards arrow Z n S O subscript 4 end subscript plus H subscript 2 end subscript$

In which of the following is the cell the overall cell reaction is: $Z n plus H subscript 2 end subscript S O subscript 4 end subscript rightwards arrow Z n S O subscript 4 end subscript plus H subscript 2 end subscript$

Chemistry-General

parallel

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