Physics-
General
Easy

Question

For the network shown in the figure the value of the current i is

  1. fraction numerator 9 V over denominator 35 end fraction    
  2. fraction numerator 5 V over denominator 18 end fraction    
  3. fraction numerator 5 V over denominator 9 end fraction    
  4. fraction numerator 18 V over denominator 5 end fraction    

The correct answer is: fraction numerator 5 V over denominator 18 end fraction


    The given network is a balanced Wheatstone bridge. It's equivalent resistance will be R equals fraction numerator 18 over denominator 5 end fraction capital omega
    So current from the battery i equals fraction numerator V over denominator R end fraction equals fraction numerator V over denominator 18 divided by 5 end fraction equals fraction numerator 5 V over denominator 18 end fraction

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