Physics-
General
Easy

Question

Four identical capacitors are connected as shown in diagram. When a battery of 6 V is connected between A and B, the charge stored is found to be 1.5 mu C. The value of C subscript 1 end subscript is

  1. 2.5 mu F    
  2. 15 mu F    
  3. 1.5 mu F    
  4. 0.1 mu F    

The correct answer is: 0.1 mu F


    The capacitance across A and B equals fraction numerator C subscript 1 end subscript over denominator 2 end fraction plus C subscript 1 end subscript plus C subscript 1 end subscript equals fraction numerator 5 over denominator 2 end fraction C subscript 1 end subscript
    As Q = CV,1.5 mu C equals fraction numerator 5 over denominator 2 end fraction C subscript 1 end subscript cross times 6
    Þ C subscript 1 end subscript equals fraction numerator 1.5 over denominator 15 end fraction cross times 1 0 to the power of negative 6 end exponent equals 0.1 cross times 1 0 to the power of negative 6 end exponent F equals 0.1 mu F.

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