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Question

If a car at rest accelerates uniformly to a speed of 144 k m divided by h in 20 s. Then it covers a distance of

  1. 20 blank m  
  2. 400 blank m  
  3. 1440 m  
  4. 2880 blank m  

The correct answer is: 400 blank m


    Here v equals 144 blank k m divided by h equals 40 m divided by s
    v equals u plus a t rightwards double arrow 40 equals 0 plus 20 cross times a rightwards double arrow a equals 2 blank m divided by s to the power of 2 end exponent
    therefore s equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent equals fraction numerator 1 over denominator 2 end fraction cross times 2 cross times open parentheses 20 close parentheses to the power of 2 end exponent=blank 400 blank m

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