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Physics-

General

Easy

Question

If in a voltaic cell 5 gm of zinc is consumed, then we get how many ampere hours? (Given that E.C.E. of Zn is $3.387 cross times 1 0 to the power of negative 7 end exponent$ kg/coulomb)

2.05
8.2
4.1
$5 \times 3.387 \times 1 0^{- 7}$

The correct answer is: 4.1

$m equals Z i t equals Z q$ ; $q equals fraction numerator 5 cross times 1 0 to the power of negative 3 end exponent over denominator 3.387 cross times 1 0 to the power of negative 7 end exponent end fraction a m p minus s e c$
or $q equals fraction numerator 5 cross times 1 0 to the power of negative 3 end exponent over denominator 3.387 cross times 1 0 to the power of negative 7 end exponent cross times 3600 end fraction a m p minus h r equals 4.1$

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