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General
Easy
Question
In a photoelectric experiment, electrons are ejected from metals X and Y by light of intensity I and frequency f. The potential difference V required to stop the electrons is measured for various frequencies. If Y has a greater work function than X; which one of the following graphs best illustrates the expected results?
The correct answer is:
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In a photoelectric experiment, the potential difference V that must be maintained between the illuminated surface and the collector so as just to prevent any electron from reaching the collector is determined for different frequencies f of the incident illumination. The graph obtained is shown. The maximum kinetic energy of the electrons emitted at frequency f1 is
In a photoelectric experiment, the potential difference V that must be maintained between the illuminated surface and the collector so as just to prevent any electron from reaching the collector is determined for different frequencies f of the incident illumination. The graph obtained is shown. The maximum kinetic energy of the electrons emitted at frequency f1 is
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then I equals
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dx is equal to
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then A+B+C is equal to
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Its corresponding velocity–time graph will be :
physics-General
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Figure (i) and (ii) below show the displacement–time graphs of two particles moving along the x–axis. We can say that :
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i)
ii)
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A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be :
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A boat is moving with velocity of 
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Physics-General
