Physics-
General
Easy

Question

In given figure, the potentiometer wire AB has a resistance of 5 capital omega and length 10 m. The balancing length AM for the emf of 0.4 V is

  1. 0.4 m    
  2. 4 m    
  3. 0.8 m    
  4. 8 m    

The correct answer is: 8 m


    E equals fraction numerator e over denominator left parenthesis R plus R subscript h end subscript plus r right parenthesis end fraction. fraction numerator R over denominator L end fraction cross times l Þ 0.4 equals fraction numerator 5 over denominator left parenthesis 5 plus 45 plus 0 right parenthesis end fraction cross times fraction numerator 5 over denominator 10 end fraction cross times l
    Þ l = 8 m

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