Physics-
General
Easy

Question

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

  1. beta    
  2. n    
  3. n to the power of negative 2 end exponent    
  4. n to the power of 2 end exponent    

The correct answer is: n to the power of 2 end exponent


    Bohr radius r equals fraction numerator epsilon subscript 0 end subscript n to the power of 2 end exponent h to the power of 2 end exponent over denominator pi Z m e to the power of 2 end exponent end fraction semicolon     therefore r proportional to n to the power of 2 end exponent

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