Physics-
General
Easy

Question

In the diagram a graph between the intensity of X-rays emitted by a molybdenum target and the wavelength is shown, when electrons of 30 keV are incident on the target. In the graph one peak is of K subscript alpha end subscript line and the other peak is of K subscript beta end subscript line

  1. First peak is of K subscript alpha end subscript line at 0.6 Å    
  2. Highest peak is of Ka line at 0.7 Å    
  3. If the energy of incident particles is increased, then the peaks will shift towards left    
  4. If the energy of incident particles is increased, then the peaks will shift towards right    

The correct answer is: Highest peak is of Ka line at 0.7 Å


    Peak of Ka is greater than peak of Kbline.

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